| Name: |
Twoeq5a - Van Laar eqs. coeff.
from azeotropic data (ethanol - n heptane) - 1st form. |
| Source: |
Cutlip, M. B. and Shacham,
M, Problem Solving in Chemical |
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Engineering with Numerical
Methods (2nd Ed.), Prentice Hall
Inc., |
| Reference/s |
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| Model: |
2 implicit equations, indep.
variables A and B |
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Average difficulty level |
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Constraints: A>0, B>0 |
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Discontinuities: Undefined
for A=0 or B=0, may be undefined for some |
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negative values of A or B. |
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Initial estimates: 1. A=0.5,
B=0.5; 2. A=1, B=1; 3. A=5, B=5; 4. A=8, B=2 |
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| Solved by |
Shacham, M., POLYMATH 5.1,
build 19, April 2, 2001 |
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| Model Eqs. |
Van Laar eqs. coeff. from
azeotropic data (ethanol - n heptane) - 1st form. |POLVER05_3 |
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EXCEL
FILE |
f(A) = log(gamma1)-A*x2^2/(A*x1/B+x2)^2
# |
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TEXT
FILE |
f(B) = log(gamma2)-B*x1^2/(x1+B*x2/A)^2
# |
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POLYMATH
FILE |
t=70.9 # |
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pw1=49 # |
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x1=(pw1/46.07)/(pw1/46.07+(100-pw1)/100.2)
# |
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P2=10^(6.9024-1268.115/(216.9+t))
# |
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P1=10^(8.04494-1554.3/(222.65+t))
# |
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gamma1=760/P1 # |
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x2=1-x1 # |
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gamma2=760/P2 # |
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g1calc=10^(A*x2^2/(A*x1/B+x2)^2)
# |
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g2calc=10^(B*x1^2/(x1+B*x2/A)^2)
# |
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A(0)=1.0 |
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B(0)=1.0 |
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| Variable/function values |
Variable |
Value |
f(x) |
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A |
1 |
2.5957E-02 |
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B |
1 |
-7.2785E-02 |
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t |
70.9 |
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pw1 |
49 |
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x1 |
0.6763 |
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P2 |
313.4462 |
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P1 |
562.4721 |
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gamma1 |
1.3512 |
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x2 |
0.3237 |
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gamma2 |
2.4247 |
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g1calc |
1.2728 |
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g2calc |
2.8671 |
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| Solution |
Variable |
Value |
f(x) |
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A |
0.7580768059470 |
-2.4980E-16 |
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B |
1.1249034445330 |
-1.6098E-15 |
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t |
70.9 |
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pw1 |
49 |
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x1 |
0.6763396823691 |
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P2 |
313.4462149790 |
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P1 |
562.4720681541 |
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gamma1 |
1.3511782060470 |
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x2 |
0.3236603176309 |
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gamma2 |
2.4246584060710 |
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g1calc |
1.3511781866300 |
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g2calc |
2.4246581829110 |
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| Additional information |
Most methods won't converge
from the 4th initial guess |