Sixeq4b

Name: Sixeq4b - Modeling of a CSTR for a complex sequence of reactions- revised form.
Source: Fogler, S. H., Personal communications (2000)
       
Reference/s Shacham, M.and Brauner N., Computers chem. Engng. (submitted, 2001)
       
Model: 6 implicit equations, indep. variables CA, CB, CC, CD, CE and T
  Average difficulty level
  Constraints: CA, CB, CC, CD and CE are nonnegative
  Discontinuities: Undefined for T=0
       
  Initial estimates: 1.(0.5, 0.01, 1, 0.01, 1, 420) 2.(0.05, 0.001, 1, 0.05, 1, 400);
  3.(0.1, 0.2, 0.5, 0.1, 0.7, 350) 2.(0.1, 0.2, 0.5, 0.1, 0.7, 380);
       
Solved by Shacham, M., POLYMATH 5.1, build 19, April 16, 2001
       
Model Eqs. Modeling of a CSTR for a complex sequence of reactions- revised form. |POLVER05_3

EXCEL FILE 

f(CA) = V*(-rA)- vo*(CAO-CA) #

TEXT FILE 

f(CB) = V*(-rB) - vo*(CBO-CB) #

POLYMATH FILE 

f(CC) = V*rC- vo*CC #
  f(CD) = V*rD - vo*CD #
  f(CE) = V*rE - vo*CE #
  f(T) = 5000*(350-T) - 25*(20+40)*(T-300) + V*SRH #
  rA = 2*r1B #
  rB = r1B+2*r2C #
  rC = -3*r1B + r2C #
  rD = -r3E - r2C #
  rE = r3E #
  r1B = -k1B*CA*CB #
  r2C = -k2C*CC*CB^2 #
  r3E = k3E*CD #
  k1B = 0.4*exp((20000/R)*(1/300-1/T)) #
  k2C = 10*exp((5000/R)*(1/310-1/T)) #
  k3E = 10*exp((10000/R)*(1/320-1/T)) #
  SRH = -rA*20000 + 2*r2C*10000 + 5000*r3E #
  R = 1.987 #
  V = 500 #
  vo = 75/3.3 #
  CAO = 25/vo #
  CBO = 50/vo #
  CA(0)=.5
  CB(0)=.01
  CC(0)=1
  CD(0)=.01
  CE(0)=1
  T(0)=420
       
Variable/function values Variable Value f(x)
  CA 0.5 2.9109E+04
  CB 0.01 1.4520E+04
  CC 1 4.3657E+04
  CD 0.01 -2.1106E+03
  CE 1 2.0918E+03
  T 420 5.92E+08
  R 1.987  
  k1B 5824.501  
  k2C 83.809  
  r1B -29.123  
  r2C -0.008  
  k3E 422.912  
  rA -58.245  
  rB -29.139  
  r3E 4.229  
  rC 87.359  
  rD -4.221  
  rE 4.229  
  SRH 1.186E+06  
  V 500.000  
  vo 22.727  
  CAO 1.100  
  CBO 2.200  
       
Solution Variable Value f(x)
  CA 0.002666326911334 2.4869E-14
  CB 0.033464055791589 3.5527E-14
  CC 0.837065955800961 2.8422E-14
  CD 0.000396698449814 4.8225E-16
  CE 0.808537855382225 1.4211E-14
  T 372.764586230922 1.7462E-10
  R 1.987  
  k1B 279.507881234417  
  k2C 39.225986593124  
  r1B -0.024939401661106  
  r2C -0.036769752446911  
  k3E 92.643973568468000  
  rA -0.049878803322212  
  rB -0.098478906554928  
  r3E 0.036751720699192  
  rC 0.038048452536407  
  rD 0.000018031747719  
  rE 0.036751720699192  
  SRH 445.939621001986  
       
Infeasible solution Variable Value f(x)
  CA -0.002818489527374 -9.2371E-14
  CB -0.035077648835548 -8.5265E-14
  CC 0.812393532255130 -1.2434E-13
  CD 0.000433468786528 1.3312E-14
  CE 0.841400733249403 -3.9080E-14
  T 371.421990965300 -1.5716E-09
  R 1.987  
  k1B 253.515466973549  
  k2C 38.280400798793  
  r1B -0.025064056580168  
  r2C -0.038265191001633  
  k3E 88.231238473553200  
  rA -0.050128113160335  
  rB -0.101594438583434  
  r3E 0.038245487874973  
  rC 0.036926978738869  
  rD 0.000019703126660  
  rE 0.038245487874973  
  SRH 428.485882548900  
       
Additional information Some algorithms converge to an infeasible solution
  from initial guesses 3 and 4.