Equilibrium conversion in a tubular reactor - revised form  |POLVER05_1
f(xa)=-ra/FA0  #
T=313  #
P0=10  #
FA0=20*P0/(0.082*450)  #
k1=1.277*1.e9*exp(-90000/(8.31*T))  #
k2=1.29*1.e11*exp(-135000/(8.31*T))  #
xa1=1+xa  #
ra = (-k1*P0*(1-xa)/xa1+k2*P0*P0*xa*xa/(xa1^2))  #
xa(min)=0.75, xa(max)=1.2