Equilibrium conversion in a tubular reactor - original form |POLVER05_1
f(xa)=-ra/FA0 #
T=313 #
P0=10 #
FA0=20*P0/(0.082*450) #
k1=1.277*1.e9*exp(-90000/(8.31*T)) #
k2=1.29*1.e11*exp(-135000/(8.31*T)) #
den=1+7*P0*(1-xa)/(1+xa) #
xa1=1+xa #
ra = (-k1*P0*(1-xa)/xa1+k2*P0*P0*xa*xa/(xa1^2))/den #
xa(min)=.75
xa(max)=1.2