% Problem 2 %Tae H Han %University of Washington %August 6, 1997 % % % 2.4 Problem Statement % Xylene, styrene, toluene, and benzene are to be separated with the % array of distillation columns in Figure 1. F, D, B, D1, B1, D2, and % B2 are the molar flow rates in mol/min. % % Material balances on individual components on the overall separation % train yield the equation set(6): % Xylene: 0.07D1+0.18B1+0.15D2+0.24B2=0.15*70 % Styrene: 0.04D1+0.24B1+0.10D2+0.65B2=0.25*70 % Toluene: 0.54D1+0.42B1+0.54D2+0.10B2=0.40*70 % Benzene: 0.35D1+0.16B1+0.21D2+0.01B2=0.20*70 % A=[0.07 0.18 0.15 0.24 0.04 0.24 0.10 0.65 0.54 0.42 0.54 0.10 0.35 0.16 0.21 0.01]; f = [0.15*70 0.25*70 0.40*70 0.2*70]; disp('Solution for D1 B1 D2 B2 is:') X = A\f' % solution is 26.25 17.50 8.75 17.50 % Overall balances and individual components balances on column#2 can % be used to determine the molar flow rate and mole fractions from the % equation of stream D from(7): % % Molar Flow Rates: D=D1+B1 % % Xylene: X_Dx*D=0.07D1+0.18B1 % Styrene: X_Ds*D=0.04D1+0.24B1 % Toluene: X_Dt*D=0.54D1+0.42B1 % Benzene: X_Db*D=0.35D1+0.16B1 % % Where: X_Dx=mole fraction of Xylene % X_Ds=mole fraction of Styrene % X_Dt=mole fraction of Toluene % X_Db=mole fraction of Benzene % %Use the balance over column#2 D1 = X(1); B1 = X(2); disp ('Solve for Column 2') D=D1+B1 %43.75 mol/min X_Dx=(0.07*D1+0.18*B1)/D %0.114 mole fraction X_Ds=(0.04*D1+0.24*B1)/D %0.120 mole fraction X_Dt=(0.54*D1+0.42*B1)/D %0.492 mole fraction X_Db=(0.35*D1+0.16*B1)/D %0.274 mole fraction % Similarly, overall balances and individual component balances on % column #3 can be used to determine the molar flow rate and mole % fractions of stream B from the equation set(8): % % Molar Flow Rates: B=D2+B2 % % Xylene: X_Bx*B=0.15D2+0.24B2 % Styrene: X_Bs*B=0.10D2+0.65B2 % Toluene: X_Bt*B=0.54D2+0.10B2 % Benzene: X_Bb*B=0.21D2+0.01B2 % %Use the balance over column#3 D2 = X(3); B2 = X(4); disp('Solve for Column 3') B=D2+B2 %26.25 mol/min X_Bx=(0.15*D2+0.24*B2)/B %0.2100 mole fraction X_Bs=(0.10*D2+0.65*B2)/B %0.4667 mole fraction X_Bt=(0.54*D2+0.10*B2)/B %0.2467 mole fraction X_Bb=(0.21*D2+0.01*B2)/B %0.0767 mole fraction